9x^2-200x+455=0

Solution for 9x^2-200x+455=0 equation:

9x^2-200x+455=0

a = 9; b = -200; c = +455;
Δ = b2-4ac
Δ = -2002-4·9·455
Δ = 23620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23620}=\sqrt{4*5905}=\sqrt{4}*\sqrt{5905}=2\sqrt{5905}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-2\sqrt{5905}}{2*9}=\frac{200-2\sqrt{5905}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+2\sqrt{5905}}{2*9}=\frac{200+2\sqrt{5905}}{18}
$